Answer:
Escape speed of the rocket, v = 4206.86 m/s
Explanation:
Mass of the rocket, [tex]m=2\times 10^6\ kg[/tex]
We need to find the escape speed of the rocket with respect to its gravitational interaction with the Sun. It is given by :
[tex]v=\sqrt{\dfrac{2GM}{R}}[/tex]
Where
G is the universal gravitational constant
R is the distance
[tex]v=\sqrt{\dfrac{2\times 6.67\times 10^{-11}\times 1.99\times 10^{30}}{150\times 10^{11}}}[/tex]
v = 4206.86 m/s
So, the escape speed of the rocket is 4206.86 m/s. Hence, this is the required solution.
