Explanation:
It is given that,
Current, [tex]I=90\ mA=90\times 10^{-3}\ A[/tex]
Time taken, t = 12 h = 43200 s
(a) We need to find the charge released. Current flowing is given by :
[tex]I=\dfrac{q}{t}[/tex]
[tex]q=I\times t[/tex]
[tex]q=90\times 10^{-3}\times 43200[/tex]
q = 3888 C
(b) Terminal voltage, V = 1.5 V
Energy delivered is given by :
[tex]W=E=V\times q[/tex]
[tex]E=1.5\ V\times 3888\ C[/tex]
E = 5832 Joules
Hence, this is the required solution.
