Answer: Yes it has suitable concentration for titration of 12.0 ml of solution required 30.6 ml of 1.65 M HCl to reach the end point.
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
According to the neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of [tex]HCl[/tex] solution = 1.65 M
[tex]V_1[/tex] = volume of [tex]HCl[/tex] solution = 30.6 ml
[tex]M_2[/tex] = molarity of [tex]NaOH[/tex] solution = ? M
[tex]V_2[/tex] = volume of [tex]NaOH[/tex] solution = 12.0 ml
[tex]n_1[/tex] = valency of [tex]HCl[/tex] = 1
[tex]n_2[/tex] = valency of [tex]NaOH[/tex] = 1
[tex]1\times 1.65\times 30.6=1\times M_2\times 12[/tex]
[tex]M_2=4.20M[/tex]
As the concentration of NaOH is 4.20 M and it lies between 3M to 6M ,thus it is suitable.