Answer:
174,957.143 grams of potassium and 89,228.478 grams of potassium nitrate will be needed.
Explanation:
[tex]5K +KNO_3\rightarrow 3K_2O + N[/tex]
Mass of nitrogen = 27 lbs = 12,247 g
1 lbs = 453.592 g
Moles of nitrogen = [tex]\frac{12,247 g}{14 g/mol}=874.786 mol[/tex]
According to reaction, 1 mole of nitrogen is produced from 5 moles of potassium and 1 mole of potassium nitrate.
Then 874.786 mol of nitrogen will be obtained from :
[tex]\frac{5}{1}\times 874.786 mol=4,373.928 mol[/tex] of potassium.
Then 874.786 mol of nitrogen will be obtained from :
[tex]\frac{1}{1}\times 874.786 mol=874.789 mol[/tex] of potassium nitrate.
Mass of 4,373.928 moles of potassium:
[tex]4,373.928 mol\times 40 g/mol=174,957.143 g[/tex] of potassium
Mass of 874.789 moles of potassium nitrate:
[tex]874.789 mol\times 102 g/mol=89,228.478 g[/tex] of potassium nitrate
