A ray of light in air is incident on a flat piece of glass at an angle of 0 = 54° with respect to the surface. The glass has index of refraction n = 1.8. What is the angle of the refracted ray?

Respuesta :

Answer:

26.71°

Explanation:

Using Snell's law as:

[tex]n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}[/tex]

Where,  

[tex]{\theta_i}[/tex]  is the angle of incidence  ( 54.0° )

[tex]{\theta_r}[/tex] is the angle of refraction  ( ? )

[tex]{n_r}[/tex] is the refractive index of the refraction medium  (glass, n=1.8)

[tex]{n_i}[/tex] is the refractive index of the incidence medium (air, n=1)

Hence,  

[tex]1\times {sin54.0^0}={1.8}\times{sin\theta_r}[/tex]

Angle of refraction = [tex]sin^{-1}\ 0.4495[/tex] = 26.71°