Answer:
[tex]P(x)=2x+13x^{2}+43x^{3}[/tex]
Step-by-step explanation:
We follow the procedure to find each term of the Taylor series:
[tex]y'=8sin(y)+2e^{5x}\\y'(0)=8sin(0)+2e^{5(0)}\\y'(0)=2\\y''=y'8cos(y)+10e^{5x}\\y''(0)=2*8cos(0)+10e^{5(0)}\\y''(0)=26\\y'''=y''8cos(y)-(y')^{2}8sin(y)+50e^{5x}\\y'''(0)=26*8cos(0)-(2)^{2}8sin(0)+50e^{5(0)}\\y'''(0)=258[/tex]
Now that we have the first three non-zero terms, we proceed to set the Taylor series:
[tex]P(x)=0+\frac{2}{1!} x+\frac{26}{2!} x^{2}+\frac{258}{3!} x^{3}[/tex]
Then we proceed to solve the polynomial:
[tex]P(x)=2x+13x^{2}+43x^{3}[/tex]