Respuesta :

encali2008

Answer:  2.7m/s

Explanation:

cyclist fight only against the component of weight along the road (no friction) , that is:

fx =Wsin6° = mgsin6°=68*9.8*sin6°=69.6N downward

so the force that moves the bike over the hill will be equal to fx but upward

Now we now that the power P = 0.25hp= 186.5W  is:

P=f*v  so v = P/fx  = 186.5/69.6 = 2.7m/s

Cricetus

A cyclist climb at the speed of "2.7 m/s".

Given values:

  • Angle, [tex]\Theta = 6.0^{\circ}[/tex]
  • Mass, [tex]m = 68 \ kg[/tex]
  • Power output, [tex]P = 0.25 \ hp \ or \ 186.5 \ W[/tex]

Now,

The force will be:

→ [tex]F = W Sin6^{\circ}[/tex]

or,

→ [tex]F = mg Sin6^{\circ}[/tex]

By substituting the values, we get

      [tex]= 68\times 9.8\times Sin6^{\circ}[/tex]

      [tex]= 69.6 \ N[/tex] (downwards)        

hence,

The speed of cyclist will be:

→ [tex]P=Fv[/tex]

or,

→ [tex]v = \frac{P}{F}[/tex]

     [tex]= \frac{186.5}{69.6}[/tex]

     [tex]= 2.7 \ m/s[/tex]

Thus the approach above is right.

Learn more about friction here:

https://brainly.com/question/12124079

Ver imagen Cricetus

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