Answer:2.6 h
Explanation:
Given
Total Trip distance=450 miles
Meeting starts after 10.8 hours
safe Fastest speed is 55 mi/h
so if he drives all the to the meeting with max speed then it takes [tex]=\frac{450}{55}=8.181 h[/tex]
and total allowable time is 10.8
Therefore longest time he can spend over dinner is [tex]10.8-8.181 \approx 2.6 hours [/tex]