Answer:
pH = 7
Volume of 0.0895 M KOH = 2.15 mL
Explanation:
(Assuming HNO, should be HNO₃)
The balanced chemical equation is:
HNO₃ + KOH ⇒ H₂O + KNO₃
At the equivalence point, the amount of KOH added is equivalent to the amount of HNO₃ present, which is calculated as follows:
(23.4mL)(0.0390mol/L) = 0.9126 mmol HNO₃
Since HNO₃ and KOH react in a 1:1 molar proportion, 0.9126 mmol of KOH is required to reach the equivalence point. Therefore, the volume of KOH solution required is:
(0.1926mmol) ÷ (0.0895mol/L) = 2.15 mL KOH solution
The HNO₃ and KOH react completely and neither is in excess, so only the products of the reaction remain (H₂O and KNO₃). Since KNO₃ can be considered a neutral salt, the pH at the equivalence point is 7.
