Answer:
Number of nucleosomes in [tex]2.9 * 10^9[/tex]bp is equal to [tex]1.47 * 10^7[/tex]
Explanation:
For wounding one nucleosome, total length of DNA required is equal to [tex]146[/tex] bp
The length of linker DNA in mammals is equal to [tex]50[/tex] bp
Thus , the total length of DNA that confides between two nucleosome is equal to the sum of wounding length of DNA and the linker length
[tex]= 146 + 50\\= 196[/tex]bp
Thus, in [tex]196[/tex]bp length of DNA, the total number of nucleosomes is equal to [tex]1[/tex]
Thus, number of nucleosomes in [tex]2.9 * 10^9[/tex]bp is equal to
[tex]\frac{2.9* 10^9}{196} \\1.47 * 10^7[/tex]
