Answer:
- 6.48 J K⁻¹
Explanation:
Temperature of gas = 20°C
= 273 +20 = 293 K.
As temperature is fixed , there will be no change in gas internal energy
Δ E = 0
From the relation
Δ Q = Δ E+ Δ W
Work done on the gas is 1.9 x 10³
Δ W = - 1.9 x 10³ J
Δ Q = - 1.9 x 10³ J
Δ S = Δ Q / T
=[tex]\frac{- 1.9 \times 10^3 }{293}[/tex]
= - 6.48 J K⁻¹
