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Calculate the average speed of a complete round trip in which the outgoing 280 km is covered at 97 km/h , followed by a 1.0-h lunch break, and the return 280 km is covered at 51 km/h . Express your answer to two significant figures and include the appropriate units. v¯ v ¯ = 60 km h Previous Answers Correct Part B Calculate the average velocity of the trip.

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klefenz

Answer:

59.7 km/h

Explanation:

We can consider this trip as one single 560 km trip (adding the outgoing and back parts together)

The time to complete it is:

[tex]\frac{280}{97} + 1 + \frac{280}{51} = 9.38 h[/tex]

So the average speed would be the distance transversed over the time taken:

560/9.38 = 59.7 km/h

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