Answer : The normality of the solution is, 30.006 N
Explanation :
Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.
Mathematical expression of normality is:
[tex]\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}[/tex]
or,
[tex]\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}[/tex]
First we have to calculate the equivalent weight of solute.
Molar mass of solute [tex]PO_4^{3-}[/tex] = 94.97 g/mole
[tex]\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq[/tex]
Now we have to calculate the normality of solution.
[tex]\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L[/tex]
Therefore, the normality of the solution is, 30.006 N
