A gas is contained in a vertical, frictionless piston–cylinder device. The piston has a mass of 3.2 kg and a cross-sectional area of 35 cm2. A compressed spring above the piston exerts a force of 110 N on the piston. If the atmospheric pressure is 95 kPa, determine the pressure inside the cylinder.

Respuesta :

Answer:

146.826 KPa

Explanation:

Given:

The mass of the piston = 3.2 kg

Cross-sectional area = 35 cm²

Force exerted by the spring = 110 N

Atmospheric pressure = 95 KPa

Now,

the total pressure inside the cylinder is the sum of all the pressure exerted on it i,e the pressure due the weight of the piston, pressure due to the force by the spring and the atmospheric pressure.

Now,

the pressure due to the weight of the piston = Weight / Area

= 3.2× 9.81 / 0.0035

= 31.392 / 0.0035

= 8969 Pa

= 8.969 KPa

And,

The pressure by the spring = 150 N / 0.0035

or

The pressure by the spring = 42,857 Pa = 42.857 KPa

Thus,

The total pressure

95 + 8.969 + 42.857 = 146.826 KPa

Pressure is the force applied perpendicular on the surface of the object per unit its area, where the force is distributed.

The pressure inside the cylinder is 146.826 k-Pa.

What is pressure?

Pressure is the force applied perpendicular on the surface of the object per unit its area, where the force is distributed.

Given information-

The mass of the piston is 3.2 kg.

The cross sectional area of he piston is 35 squared cm.

The force exerted by the spring is 110 N.

The atmospheric pressure is 95 k-Pa.

The pressure inside the cylinder is the sum of the all pressure applied on it.

The pressure which are applied inside the surface is atmospherics pressure, pressure due to the weight of the piston and the pressure applied by the spring.

Thus the total pressure inside the cylinder can be given as,

[tex]P_i=P_a+P_w+P_s\\P_i=95+\dfrac{3.2\times9.8}{0.0035}+\dfrac{150}{0.0035} \\P_i=146.826\rm\rm kPa[/tex]

Hence, the pressure inside the cylinder is 146.826 k-Pa.

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