Answer:
Step-by-step explanation:
given that tonya charges 20$ monthly fee and 3$ per mile of her dog-walking service.
and beth does not charge any monthly fee but charges 5$ per mile of the dog walked in.
let x be the number of miles dog has walked in a month.
the amount tonya will charge on x miles = fixed monthly fee + number of miles * charge per mile = 20+3x
and the amount beth will charge on x miles = 0+ 5*x = 5x.
we are asked to find the x-value for which beth chargeable amount = tonya chargeable amount
that is 5x = 20+3x
5x-2x = 20
2x=20
x=[tex]\frac{20}{2} = 10[/tex]
hence number of miles for which tonya and beth will charge the same amount is 10.
