Assumptions:
Explanation:
According to the attached image, the local heat flux over a flat plate can be expressed as follows,
[tex]Q = (T_{s} - T_{\infty}) \ A_s \int\limit_{A_{s}} {h} \, dA_{s}[/tex]
Where:
[tex]Q : Local \ Heat \ Flux [W]\\T_{s} : Temperature \ on \ the \ surface \ of \ the \ plate \ [K]\\T_{\infty} : Temperature \ of \ the \ room \ [K]\\h : Convective coefficient [\frac{W}{m^2 K} ]\\A_{s} : Area \ of \ the \ plate [m^{2}][/tex]
Consider an average convection coefficient,
[tex]Q = \overline{h} \ A_{s} \ (T_s -T_{\infty})[/tex]
Answer:
Then, replacing all the values in the previous expression,
[tex]Q = (250 \frac{W}{m^2 K} )(0.5m)(0.25m)(313.5K - 293.15K)\\Q= 625W[/tex]