The 240 V air conditioning motor at a residence is rated at I hp with a power factor of 0.65 (lagging). Determine the equivalent (a) impedance and (b) admittance of the ac motor.

Respuesta :

Answer:

(a) 50.20 ohm (b) [tex]0.0199ohm^{-1}[/tex]

Explanation:

e have given the power P =1 hp =745.7 W

Voltage V =240 V

Power factor [tex]cos\Phi =0.65[/tex]

We know that power [tex]P=Vicos\Phi[/tex]

So [tex]745.7=240\times i\times 0.65[/tex]

i =4.7801 A

Now according to ohm's law [tex]i=\frac{V}{Z}[/tex]

(a) So [tex]Z=\frac{V}{i}=\frac{240}{4.78}=50.20ohm[/tex]

(b) Admittance of any circuit is the inverse of the impedance

So admittance [tex]Y=\frac{1}{Z}=\frac{1}{50.20}=0.0199ohm^{-1}[/tex]