Answer:
5
Step-by-step explanation:
Let x be the number of the developers that there were in the company before the hirings, and y the number of testers.
You now that:
[tex]\frac{y}{x} = \frac{2.5}{10}[/tex]
Then,
y = [tex]\frac{2.5x}{10}[/tex]
Now:
[tex]\frac{y + n}{x + 20} = \frac{2.5}{10}[/tex]
[tex]\frac{2.5x}{10}[/tex] + n = [tex]\frac{2.5(x+20)}{10}[/tex] = [tex]\frac{2.5x}{10}[/tex] + [tex]\frac{2.5 * 20}{10}[/tex]
n = [tex]\frac{2.5 * 20}{10}[/tex] = 5
Answer:
They will need to hire 5 testers.
Step-by-step explanation:
This question can be solved using a simple rule of three.
For each 10 developers, we need 2.5 testers. So how many testers are needed for 20 developers?
10 developers - 2.5 testers
20 developers - x testes
[tex]10x = 20*2.5[/tex]
[tex]10x = 50[/tex]
[tex]x = \frac{50}{10}[/tex]
[tex]x = 5[/tex]
They will need to hire 5 testers.
