Answer:
The percentage of error in this experiment is 0.66%
Step-by-step explanation:
The value measured by a student, let's call it [tex]xm[/tex], is equal to 0.1355 M. And the real value of molarity is,let's call it [tex]xr[/tex] is equal to 0.1364.
The error in the measurement (E) is equal to the absolute difference between the real value and the measured value:
abs ( xr - xm ) = E
So in this experiment it will be equal to:
abs ( 0.1364 - 0.1355 ) = 0.0009
And the percentage of error (e) will be:
[tex]e = \frac{E}{xr}*100[/tex]
Thus,
e = 0.0009 * 100 / 0.1364 ⇒ e= 0.659 % ≈ 0.66 %
So, the percentage of error in this experiment is 0.66%
