During each cycle, a heat engine ejects 75 J of thermal energy for every 115 J of input thermal energy. This engine is used to lift a 345-kg load a vertical distance of 27.0 m at a steady rate of 52.5 mm/s. Part A How many cycles of the engine are needed to accomplish this task?

Respuesta :

Answer:

no of cycle required is 1885.3

Explanation:

given data

thermal energy Q1 = 75 J

thermal energy Q2 = 115 J

load = 3454 kg

distance = 27 m

steady rate = 52.5 mm/s

to find out

How many cycles of the engine are need

solution

we find here first work done that is express as

work done W = Q2 - Q1     ..................1

put here all these value

W = 115 - 75

work done is 40 J

so energy required is

Energy required E = m×g×h     ..................2

put here value

E = 285 × 9.8 × 27

energy required = 75411 J

so here no of cycle is

no of cycle = energy required / work done

put here value

no of cycle required = 75411 / 40

so no of cycle required is 1885.3

The number of cycles of the engine needed to accomplish the task of lifting the load by the engine is, 2282.175 cycles.

What is work energy theorem?

According to the work energy theorem, the sum of all the forces acting on a body to do a work is equal to the change in the kinetic energy of the body.

During each cycle, a heat engine ejects 75 J of thermal energy for every 115 J of input thermal energy. The net work done on the system is,

[tex]W=115-75\\W=40\rm \; J[/tex]

This engine is used to lift a 345-kg load a vertical distance of 27.0 m at a steady rate of 52.5 mm/s.

The gravitational potential energy required to lift the load is,

[tex]E=mgh\\E=345\times9.8\times72\\E=91287[/tex]

As the one cycles gives the work done of 40 J. Thus, the number of cycle required for 91287 energy is,

[tex]n=\dfrac{E}{W}\\n=\dfrac{91287}{40}\\n=2282.175[/tex]

Hence, the number of cycles of the engine needed to accomplish the task of lifting the load by the engine is, 2282.175 cycles.

Learn more about the work energy theorem here;

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