Answer:
Time taken, t = 5.69 seconds
Explanation:
It is given that,
Initial speed of the particle, u = 7.4 m/s
Deceleration of the particle, [tex]a=-1.3\ m/s^2[/tex]
We need to find the time taken by it to get back to the starting point. Let t is the time taken. So,
[tex]v=u+at[/tex]
[tex]t=\dfrac{v-u}{a}[/tex]
[tex]t=\dfrac{0-7.4}{-1.3}[/tex]
t = 5.69 seconds
So, the time taken by the particle is 5.69 seconds. Hence, this is the required solution.
