Answer:
155.25 atm
Explanation:
Distance, h = 1.6 km = 1600 m
density of water = 13.6 times less than the density of mercury
density of mercury = 13.6 x 10^3 kg/m^3
So, density of water = 1 x 10^3 kg/m^3
Pressure exerted by the water
P = distance x density of water x acceleration due to gravity
P = 1600 x 1000 x 9.8
[tex]P=1.568\times10^{8}Pa[/tex]
We know that
1 atm = 1.01 x 10^5 Pa
So, [tex]P=1.568\times10^{8}Pa[/tex] = [tex]P=\frac{1.568\times10^{8}}{1.01\times10^{5}}=155.25 atm[/tex]
