Answer:
-31.4 m/s
50.2 m
Explanation:
Given:
x₀ = 0 m
v₀ = 0 m/s
t = 3.2 s
a = -9.8 m/s²
Find: v and x
v = at + v₀
v = (-9.8 m/s²) (3.2 s) + 0 m/s
v = -31.36 m/s
x = x₀ + v₀ t + ½ at²
x = 0 m + (0 m/s) (3.2 s) + ½ (-9.8 m/s²) (3.2 s)²
x = -50.176 m
Rounding, the bag reaches a velocity of -31.4 m/s after falling a distance of 50.2 m.
