Explanation:
Given that,
Charge 1, [tex]q_1=8.01\ nC=8.01\times 10^{-9}\ C[/tex]
Charge 2, [tex]q_2=3.86\ nC=3.86\times 10^{-9}\ C[/tex]
Distance between charges, d = 1.9 m
We need to find the electrostatic force that one charge exerts on the other. It is given by :
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
[tex]F=9\times10^9\times\dfrac{8.01\times 10^{-9}\times 3.86\times 10^{-9}}{(1.9)^2}[/tex]
[tex]F=7.70\times 10^{-8}\ N[/tex]
So, the magnitude of electric force that one charge exerts on the other charge is [tex]7.70\times 10^{-8}\ N[/tex]. Hence, this is the required solution.
