Answer:
The standard deviation of a sample is 0.1343
Step-by-step explanation:
The mean of the sample is [tex]\bar x = 0.5233[/tex]
The standard deviation of a sample is given by:
[tex]S =\frac{1}{n-1} \sum (x_{i}-\bar x)^2 = \frac{1}{6-1}[(0.78 - 0.5233)^2 + (0.56 - 0.5233)^2 + (0.42 - 0.5233)^2 + (0.45 - 0.5233)^2 + (0.46 - 0.5233)^2 + (0.47 - 0.5233)^2] = \frac{1}{5}[0.6715] = 0.1343[/tex]
