Answer: 84400 Joules
Explanation:
Molar enthalpy of fusion for water = 6.008 kJ/mol
Molar heat of fusion is the energy required to convert 1 mole of solid to 1 mole of liquid.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]\text{Number of moles of water}=\frac{253g}{18g/mol}=14.06moles[/tex]
1 mole of liquid water on freezing releases energy = 6.008 kJ
Thus 14.06 moles of liquid water on freezing releases energy =[tex]\frac{6.008}{1}\times 14.06=84.4 kJ=84400Joules[/tex]
Thus 84400 Joules of energy is released when 253 g of liquid water freezes.
