Answer:
Time taken, t = 4.86 seconds
Explanation:
Given that,
Acceleration of a particular automobile, [tex]a=2\ m/s^2[/tex]
Initial speed of the automobile, u = 75 km/h = 20.83 m/s
Final speed of the automobile, v = 110 km/h = 30.55 m/s
We need to find the time taken to accelerate from u to v. Let t is the time taken. It can be calculate as :
[tex]t=\dfrac{v-u}{a}[/tex]
[tex]t=\dfrac{30.55-20.83}{2}[/tex]
t = 4.86 seconds
So, the time taken by the automobile is 4.86 seconds. Hence, this is the required solution.
Answer:
4,86 seconds
Explanation:
To answer this we first have to convert the velocity from km/hr to m/s, we will use the next conversion ratios:
[tex]\frac{75 km}{1 hr}(\frac{1000m}{1 km})(\frac{1 hour}{3600 seconds})=\frac{20,83m}{1 second}[/tex]
[tex]\frac{110 km}{1 hr}(\frac{1000m}{1 km})(\frac{1 hour}{3600 seconds})=\frac{30,55m}{1 second}[/tex]
So we have both distances, now we have to calculate the time thatit would take for the automobile to accelerate to 30,55 m/s at 2 m/s^2 using the formula for acceleration:
[tex]Acc=\frac{Vf-Vo}{time} \\Time=\frac{Vf-Vo}{Acc}\\ Time=\frac{30,55-20,83}{2,0}\\ Time=\frac{9,72}{2}\\ Time=4,86 seconds[/tex]
The time that it would take a particular car to change its velocity from 75km/hr to 110 km/hr at an acceleration rate of 2 m/s will be 4,86 seconds.
