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What is the molar solubility of magnesium carbonate ( MgCO3 ) in water? The solubility-product constant for MgCO3 is 3.5 × 10-8 at 25°C.

Respuesta :

pstnonsonjoku

Answer:

1.75 ×10^-8 moldm-3

Explanation:

MgCO3(s) <----------> Mg^2+(aq) + CO3^2-(aq)

Ksp= 2x

x= Ksp/2

But Ksp= 3.5 × 10^-8 mol^2dm^-6

x= 3.5 × 10^-8/2

x= 1.75 ×10^-8 moldm-3

dsdrajlin

The molar solubility of magnesium carbonate, whose Ksp is 3.5 × 10⁻⁸, is 1.9 × 10⁻⁴ M.

Let's consider the solution of MgCO₃ in water.

MgCO₃(s) ⇄ Mg²⁺(aq) + CO₃²⁻(aq)

We can relate the molar solubility (S) to the solubility product constant (Ksp) through an ICE chart.

        MgCO₃(s) ⇄ Mg²⁺(aq) + CO₃²⁻(aq)

I                               0                 0

C                             +S              +S

E                               S                S

The solubility product constant (Ksp) is:

[tex]Ksp = [Mg^{2+} ][CO_3^{2-} ]= S.S = S^{2} \\\\S = \sqrt{Ksp} = \sqrt{3.5 \times 10^{-8} } = 1.9 \times 10^{-4} M[/tex]

The molar solubility of magnesium carbonate, whose Ksp is 3.5 × 10⁻⁸, is 1.9 × 10⁻⁴ M.

Learn more: https://brainly.com/question/4736767

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