Question 1:
For this case we must find the value of the following expression:
[tex]4 ^ 3-3 ^ 3[/tex]
So we have to:
[tex]4 ^ 3 = 4 * 4 * 4 = 4 ^ 2 * 4 = 16 * 4 = 64\\3 ^ 3 = 3 * 3 * 3 = 3 ^ 2 * 3 = 9 * 3 = 27[/tex]
Substituting we have:
[tex]64-27 =\\37[/tex]
Thus, the value of the expression is 37.
Answer:
[tex]4 ^ 3-3 ^ 3 = 37[/tex]
Option C
Question 2:
For this case we have the following expression:
[tex]2 * 3 ^ 2[/tex]
We must simplify it!
We have to:
[tex]3 ^ 2 = 3 * 3 = 9[/tex]
Rewriting the expression we have
[tex]2 * 9 =[/tex]
2 times 9 is 18.
Finally we have to:
[tex]2 * 3 ^ 2 = 18[/tex]
Answer:
[tex]2 * 3 ^ 2 = 18[/tex]
Option B
Question 3:
For this case we have that by definition, the perimeter of a square is given by:
[tex]P = 4l[/tex]
Where:
l: It's the side of the square
In this case they tell us that:
[tex]l = 50 \ in[/tex]
Thus:
[tex]P = 4 * 50\\P = 200 \ in[/tex]
Now we must do a conversion. By definition we have to:
1 foot equals 12 inches. So:
[tex]200 \ in * \frac {1} {12} * \frac {ft} {in} = \frac {50} {3} ft = 16.67ft\\[/tex]
Answer:
The perimeter of the garden is [tex]16.67 \ ft[/tex]
Question 4:
For this case we have to:
Let "p" be the variable that represents the number of pages Nora read yesterday.
If today I read 6 more than yesterday, then we can write the following expression:
[tex]p + 6[/tex]
So, the number of pages that Nora read today is [tex]p + 6[/tex]
ANswer:
The number of pages that Nora read today is[tex]p + 6[/tex]
Question 5:
For this case we have that by definition, the area of a triangle is given by:
[tex]A = \frac {b * h} {2}[/tex]
Where:
b: It is the base of the triangle
h: It is the height
We have as data that:
[tex]b = 5 \ cm\\h = 8 \ cm[/tex]
Substituting we have:[tex]A = \frac {5 * 8} {2} = \frac {40} {2} = 20 \ cm ^ 2[/tex]
The area of the triangle is[tex]20 \ cm ^ 2[/tex]
Answer:
Option B
