Compute the voltage drop along a 26-m length of household no. 14 copper wire (used in 15-A circuits). The wire has diameter 1.628 mm and carries a 13-A current. The resistivity of copper is 1.68×10−8Ω⋅m. Express your answer to two significant figures and include the appropriate units

Respuesta :

Answer:

V= 2.7 [v]

Explanation:

The value of the resistance is given by:

[tex]R=L*\frac{Rho}{A}\\\\where:\\R=resistance\\L=Lenght\\Rho=Resistivity\\A=Transversal -Area[/tex]

so:

[tex]R=26m*\frac{(1.68*10^{-8}ohm*m)}{\pi *(\frac{1.628*10^{-3}m}{2})^2}\\R=0.21 Ohm[/tex]

We can calulate the voltage dropped using the Ohm's law:

[tex]V=I*R\\V=13A*0.21Ohm=2.7V[/tex]

The voltage across the circuit is 2.73 Volts.

How do you calculate the voltage across the circuit?

Given that length of the household is 26 m, the diameter of the wire is 1.628 mm, the current is 13 A. The resistivity is 1.68×10−8Ω⋅m.

The resistance on the copper wire is calculated as given below.

[tex]R = l \dfrac {\rho}{A}[/tex]

Where R is the resistance, A is the cross-sectional area, l is the length and [tex]\rho[/tex] is the resistivity.

Substituting the values, we get the resistance.

[tex]R = 26 \times \dfrac { 1.68\times 10^{-8}}{3.14 \times (\dfrac {1.628\times 10^{-3}}{2})^2}[/tex]

[tex]R = 0.21 \;\rm ohm[/tex]

The voltage can be calculated as given below.

[tex]V = I\times R[/tex]

[tex]V = 13 \times 0.21[/tex]

[tex]V = 2.73\;\rm V[/tex]

Hence we can conclude that the voltage across the circuit is 2.73 Volts.

To know more about the voltage and current, follow the link given below.

https://brainly.com/question/10254698.

Otras preguntas