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4. The specific heat of aluminum is 0.902 J/g. If a metal smith has 300g of aluminum and wants to melt it down to make a lock. He increases the temperature from 20 to 200. How much heat does he need to apply?

Respuesta :

willjohnsonnguyen

Answer:

Q = 48708 J

Step-by-step explanation:

Q = mcΔt

Q = 300 g x (0.902 J/g°C ) x (200°C - 20°C)

Q = 300 g x (0.902 J/g°C ) x (180°C)

Q = 48708 J

The heat that should be applied is Q = 48708 J

Given information:

The specific heat of aluminum is 0.902 J/g. If a metal smith has 300g of aluminum

Calculation of the heat:

[tex]Q = mc\Delta t\\\\Q = 300 g \times (0.902 J/gC ) \times (200C - 20C)\\\\Q = 300 g \times (0.902 J/gC ) \times (180C)[/tex]

Q = 48708 J

Learn more about the heat here: https://brainly.com/question/24390508

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