Answer:[tex]7.11\times 10^{3} m/s^2[/tex]
Explanation:
Given
Drum Radius=90 cm
radius =45 cm
N=1200 rev/min
Time(t)=24 s
[tex]\omega =\frac{2\pi N}{60}=40\pi rad/s[/tex]
[tex]\omega =\omega _0+\alpha t[/tex]
[tex]40\pi =0+\alpha 24[/tex]
[tex]\alpha =5.23\pi rad/s^2[/tex]
Now radial acceleration[tex]=\omega ^2r=(40\pi )^2\times 0.45=7107.95 rad/s^2[/tex]
Tangential acceleration[tex]=\alpha t=5.23\times 0.45=2.35[/tex]
Net acceleration after 1 sec will be
[tex]a_{net}=\sqrt{7107.95^2+2.35^2}=7107.96 m/s^2=7.11\times 10^{3}[/tex]
