Answer:
U=0.22475 Joules
Explanation:
The electric potential energy between 2 charges can be calculated with the formula [tex]U=k\frac{q_1q_2}{r}[/tex], where (in S.I.):
[tex]k=8.99\times10^{9} Nm^{2}C^{-2}[/tex] is the Coulomb constant
[tex]q_1=q_2=5.00\times10^{-6}C[/tex] are the values of the charges
[tex]r=1.00m[/tex] their separation
So we have [tex]U=k\frac{q_1q_2}{r}=0.22475J[/tex]