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When taking a 11 question multiple choice test, where each question has 4 possible answers, it would be unusual to get 3 Incorrect or more questions correct by guessing alone. Note: Of course it would be unusual to get 11 questions correct. You need to enter the smallest possible number of questions to make getting "that many correct" unusual.

Respuesta :

Manetho

Answer:

6

Step-by-step explanation:

probability of answering a question correct p=1/4

let minimum number number of question that would be unusual =n

hence from binomial distribution P(X>=n) <0.05

[tex]\sum_{x=n}^{11}\binom{11}{x}(1/4)^{x}(3/4)^{11-x} <0.05[/tex]

by solving:

n=6

it would be unusual to get 6 or more questions correct by guessing alone.

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