Answer:
[tex]t=39days[/tex]
Explanation:
[tex]P(t)=2t+8t+110=10t+110[/tex]
We need to find how many days will take for the fish population to reach a population of 500. This happens when:
[tex]P(t)=500=10t+110[/tex]
Isolate "t" to one side of the equation by subtracting 100 to both sides:
[tex]10t=500-110[/tex]
[tex]10t=390[/tex]
Finally, divide both sides by 10
[tex]t=\frac{390}{10}=39[/tex]