Rosa says she can break this array(6 rows,8 in each row) into 3 different sets of two smaller arrays.Is Rosa correct.Explain

1st array [tex]5\times 8[/tex] (5 rows and 8 columns) and 2nd array [tex]1\times 8[/tex] (1 row and 8 columns);
1st array [tex]4\times 8[/tex] (4 rows and 8 columns) and 2nd array [tex]2\times 8[/tex] (2 rows and 8 columns);
1st array [tex]3\times 8[/tex] (3 rows and 8 columns) and 2nd array [tex]3\times 8[/tex] (3 rows and 8 columns);
1st array [tex]6\times 1[/tex] (6 rows and 1 column) and 2nd array [tex]6\times 7[/tex] (6 rows and 7 columns);
1st array [tex]6\times 2[/tex] (6 rows and 2 columns) and 2nd array [tex]6\times 6[/tex] (6 rows and 6 columns);
1st array [tex]6\times 3[/tex] (6 rows and 3 columns) and 2nd array [tex]6\times 5[/tex] (6 rows and 5 columns);
1st array [tex]6\times 4[/tex] (6 rows and 4 columns) and 2nd array [tex]6\times 4[/tex] (6 rows and 4 columns).

So, there are even more than 3 different ways.

MrRoyal MrRoyal · Answer 2 · 2021-10-22T22:53:00+02:00

Arrays are dataset that are represented in rows and columns

Rosa's claim is correct.

From the question, we have:

[tex]\mathbf{Row = 6}[/tex]

[tex]\mathbf{Column = 8}[/tex]

The number (n) of elements in the array is:

[tex]\mathbf{n = Row \times Column }[/tex]

So, we have:

[tex]\mathbf{n = 6 \times 8}[/tex]

[tex]\mathbf{n = 48}[/tex]

Express as sum of three numbers

[tex]\mathbf{n = 12 + 16 + 20}[/tex]

Express each term as a product

[tex]\mathbf{n = 2 \times 6 + 4 \times 4 + 5 \times 4}[/tex]

The above expression means that, the array can be split to:

Hence, Rosa is correct.