Answer:
Diameter of the wire is 0.119 mm.
Explanation:
Density of the metal = [tex]\rho =19.3 g/cm^3[/tex]
Mas of the wire = m = 42.9 mg = 0.0429 g
1 mg = 0.001 g
Let the radius of the wire be r
Length or height of the wire = h = 0.200 m = 20 cm
1 m = 100 cm
Volume of the wire = V
[tex]V=\pi r^2 h=3.14\times r^2\times 20 cm[/tex]
[tex]\rho =\frac{m}{V}[/tex]
[tex]19.3 g/cm^3=\frac{0.0429 g}{3.14\times r^2\times 20 cm}[/tex]
[tex]r=\sqrt{\frac{0.0429 g}{3.14\times 20 cm\times 19.3 g/cm^3}}[/tex]
r = 0.00595 cm = 0.0595 mm (1 cm = 10 mm)
Diameter of the wire = d = 2r = 0.119 mm.
