Explanation:
The initial velocity at which the ball is struck is:
v
A
=
80
m
/
s
The angle of inclination of the surface is:
α
=
10
∘
The angle at which ball is projected is:
β
=
45
∘
The total angle of inclination of projectile from horizontal is
θ
=
α
+
β
Answer:
Speed at which it strikes the ground= 67.4ft/s
Time of flight= 3.57secs
Explanation:
(Va)x= 80cos(10+45)°= 44.886
(Va)y= 80sin(10+45)°= 65.532
S=So + Vot + 1/2at^2
d sin 10°= 0 + 65.532t + 1/2 (-32.2)t^2
0.17d= 0 + 65.532t + (-16.1)t^2
Solving the equation gives
d=166ft
t= 3.57seconds
(Vb)x= (Va)x= 45.886
(Vb)y= 65.532 - 32.2(3.57)
(Vb)y = -49.357
Vb= sqrt(45.886^2+(-49.357^2))
Vb= 67.4ft/s
