Respuesta :
Answer:
a) -6.48 m/s²
b) a = 0.661g
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
[tex]v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-\left(\frac{87}{3.6}\right)^2}{2\times 45}\\\Rightarrow a=-6.48\ m/s^2[/tex]
Acceleration of the car is -6.48 m/s²
g = 9.81 m/s²
[tex]\frac{a}{g}=\frac{6.48}{9.81}\\\Rightarrow \frac{a}{g}=0.661\\\Rightarrow a=0.661g[/tex]
a = 0.661g
Answer:[tex]6.49 m/s^2[/tex]
Explanation:
Given
distance =45 m
initial velocity(u)[tex]=87 km/hr\approx 24.1667 m/s[/tex]
Final velocity(v)=0
[tex]v^2-u^2=2as[/tex]
[tex]0-(24.1667)^2=2\times a\times 45[/tex]
[tex]a=\frac{584.029}{2\times 45}[/tex]
[tex]a=-6.49 m/s^2[/tex]
acceleration in terms of g
[tex]\frac{a}{g}=0.662[/tex]
acceleration=0.662g
