Answer:
[tex]d=d_0+v_0t+\frac{at^2}{2}[/tex]; [tex]v=v_0+at[/tex]
[tex]y=y_0+v_{0y}t+\frac{gt^2}{2}[/tex]; [tex]x=x_0+v_{0x}t[/tex]
[tex]v_y=v_{0y}+gt[/tex]; [tex]v_x=v_{0x}[/tex]
Explanation:
The equations of accelerated motion regarding distance, velocity, acceleration are:
[tex]d=d_0+v_0t+\frac{at^2}{2}[/tex]
[tex]v=v_0+at[/tex]
If the object were in free fall, these would be (taking the downward direction as positive):
[tex]y=y_0+v_{0y}t+\frac{gt^2}{2}[/tex]
[tex]x=x_0+v_{0x}t[/tex]
[tex]v_y=v_{0y}+gt[/tex]
[tex]v_x=v_{0x}[/tex]
Other equations can also be derived from the original ones, like for example [tex]v^2=v_0^2+2a(d-d0)[/tex]
