Answer:
[tex]n=6.0332\times 10^{14}per second[/tex] photon per second
Explanation:
We have given power of the incident light [tex]P=200\times 10^{-6}=2\times 10^{-4}W[/tex]
Time = 1 sec
We know that energy E = power × time = [tex]2\times 10^{-4}\times 1=2\times 10^{-4}j[/tex]
Wavelength of light [tex]\lambda =600nm=600\times 10^{-9}m[/tex]
We know that energy pf each photon is given by [tex]E=\frac{hc}{\lambda }[/tex]
Let there are n numbers of photon [tex]\frac{nhc}{\lambda }=2\times 10^{-4}[/tex]
[tex]\frac{n\times 6.6\times 10^{-34}\times 3\times 10^8}{600\times 10^{-9} }=2\times 10^{-4}[/tex]
[tex]n=6.0332\times 10^{14}per second[/tex]
