Answer:
At the same rate 18 carburetors out of 1,050 could be expected to be detective.
Step-by-step explanation:
The number of carburetors tested = 175
Defective pieces out o f 175 = 3
So, ratio of defected to tested = 3 : 175
Now, the number of carburetors tested in second batch = 1,050
Here, let the defective pieces = m
So, by the Ratio of Proportion,
[tex]\frac{3}{175} = \frac{m}{1050}[/tex]
or, [tex]m = \frac{1050 \times 3}{175} = 18[/tex]
⇒ m = 18
Hence, at the same rate 18 carburetors out of 1,050 could be expected to be detective.