Answer:
[tex]t=\frac{ln(3)}{0.025}[/tex]
Step-by-step explanation:
we know that
The formula to calculate continuously compounded interest is equal to
[tex]A=P(e)^{rt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
e is the mathematical constant number
we have
[tex]P=\$4,000\\r=2.5\%=2.5/100=0.025\\A=\$12,000[/tex]
substitute in the formula above
[tex]12,000=4,000(e)^{0.025t}[/tex]
[tex]3=(e)^{0.025t}[/tex]
Apply ln both sides
[tex]ln(3)=ln[(e)^{0.025t}][/tex]
[tex]ln(3)=(0.025t)ln(e)[/tex]
Remember that
[tex]ln(e)=1[/tex]
[tex]ln(3)=(0.025t)[/tex]
[tex]t=\frac{ln(3)}{0.025}[/tex]
[tex]t=43.9\ years[/tex]