Answer:
1st even integer = 2
2nd even integer = 4
3rd even integer = 6
Step-by-step explanation:
Let the consecutive even integers be:
1st = 2(x)
2nd= 2(x +1) = 2x + 2
3rd = 2(x + 2) = 2x + 4
According to Given conditions:
7(2x) = 4 + 2x +2 + 2x + 4
By Simplifying:
14x = 10 + 4x
Subtracting 4x from both sides
14x - 4x = 10 + 4x -4x
10x = 10
Dividing both sides by 10 we get:
x = 1
Now putting value of x in supposed integers:
1st even integer = 2(1) = 2
2nd even integer = 2(1)+2 = 4
3rd even integer = 2(1) + 4 = 6
I hope it will help you!
