Answer:
d. moving at [tex]3.1 m/s^2[/tex]
Explanation:
We can solve the problem by applying Newton's second law:
[tex]F=ma[/tex] (1)
where
F is the net force on the object
m is the mass of the object
a is its acceleration
Here we are only interested in the motion of the object along the horizontal direction. There are two forces acting on the object in this direction:
- The force [tex]F_A[/tex], pushing to the right, with magnitude 8.4 N
- The force [tex]F_f[/tex], pulling to the left, with magnitude 2.2 N
So, we can rewrite (1) as
[tex]F_A - F_f = ma[/tex]
Where:
[tex]F_A = 8.4 N\\F_f = 2.2 N\\m = 2.0 kg[/tex]
And solving for a, we find the acceleration:
[tex]a=\frac{F_A-F_f}{m}=\frac{8.4-2.2}{2.0}=3.1 m/s^2[/tex]
and the direction is the same as the net force, so to the right.
