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Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.0677 V. How much work is done by the electric force when a sodium ion (charge = +e) moves from the outside to the inside?

Respuesta :

Answer: Recall that

Work (W) = - e × ∆V

Where

Charge of electron= 1.6 × 10^ -19 c

And from the question we were given change in potential as = -0.0677V

Work = - (1.6 × 10^-19) × (-0.0677)

Work= 1.0832 × 10^-20J

Therefore the work done by the electric force when a sodium ion (charge = +e) moves from the outside to the inside is 1.0832×10^-20

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