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John is 5 years older than Mary. In 10 years, twice John's age decreased by Mary's age is 35, and John's age will be twice Mary's current age. Find their ages now. If x is Mary's age now and y is John's age now, which system of equations could not be used to solve the problem?

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ofentsemaphalla

Answer:

John is 20 and Mary is 15.

Explanation:

Let John = X and Mary = Y be the present age.  

X = Y+5

2(X+10)-(Y+10) = 35

2(Y+5+10)-(Y+10) = 35

2Y+30-Y-10=35

Y=15

X=20

Therefore: 2*30-25=35

In other words, in ten years' time, Johns age will be double the age of Mary: 30=2*15"

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