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Answer:
Compound 1. Sulfur Dioxide
Compound 3. Dichloromethane
Compound 4. Phosphorus Trichloride
(figure attached)
Explanation:
Compound 1. Sulfur Dioxide
Polar compound
Through the Lewis structure it is confirmed that SO₂ is a polar compound, because it is an asymmetric compound having two regions of different polarity. The lower region having oxygen groups is more electronegative then the upper region.
Compound 2. Carbon Dioxide
Non polar Compound
Through the Lewis structure it is confirmed that CO₂ is a non polar compound, because it is a symmetric compound having two regions of same polarity. The left region and the right region both contains oxygen groups having same electronegativity.
Compound 3. Dichloromethane
Polar compound
Through the Lewis structure it is confirmed that CH₂Cl₂ is a polar compound, because it is an asymmetric compound having two regions of different polarity. Two chlorine atoms are attached to it and as we know that chlorine is a more electronegative element than hydrogen so it attracts the bonding pair of electrons towards itself which creates polarity.
Compound 4. Phosphorus Trichloride
Through the Lewis structure it is confirmed that PCl₃ is a polar compound, because three chlorine atoms attached to it and as we know that chlorine is a more electronegative element so it attracts the bonding pair of electrons towards itself which creates polarity.
The [tex]\rm \bold{ SO_2}[/tex], [tex]\rm \bold{ CH_2Cl_2}[/tex], and [tex]\rm \bold{ PCl_3}[/tex] are polar compounds.
As we know the polarity in molecules arises due to the difference in electronegativity between there constituent atoms.
Here,
[tex]\rm \bold{ CO_2}[/tex], is symmetric molecule hence, the electronegativity is balanced by oxygen atoms. hence it is a non-polar molecule.
[tex]\rm \bold{ SO_2}[/tex], become asymmetric due to resonance, This result in the formation two regions with high and low electron density. This cause polarity.
[tex]\rm \bold{ CH_2Cl_2}[/tex] is an asymmetric compound having two regions of different polarity. hence a polar compound.
[tex]\rm \bold{ PCl_3}[/tex], the difference in electronegativities between P and Cl is high. hence form a polar molecule.
Hence, we can conclude that the [tex]\rm \bold{ SO_2}[/tex], [tex]\rm \bold{ CH_2Cl_2}[/tex], and [tex]\rm \bold{ PCl_3}[/tex] are polar compounds.
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