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What is the count of possible passwords if the characters in the passwords are all either letters or digits and the length of the password is 6 and it must contain at least one digit and one letter? (Assume all letters are lower case, so there are only 26 letters). Group of answer choices

Respuesta :

MechEngineer

Answer:

1857866560  

Explanation:

10 digits + 26 letters = 36 possible combination for each of the character in the password.

Since the password has a length of 6, there are

[tex]36 * 36 * 36 * 36 * 36 * 36 = 36^6 = 2176782336 [/tex] possible password combination

Since we need to make sure there's at least 1 letter and 1 number in the password, we can subtract (remove) the above result by the cases where password is made up all letters and all numbers

All numbers: [tex] 10^6 = 1000000[/tex] cases

All letters: [tex]26^6 = 308915776[/tex] cases

So the number of possible combination password where there's at least 1 letter and 1 number is:

[tex]2176782336-1000000-308915776=1857866560\approx 1.86*10^9[/tex]

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