So as we know,
[tex]F_1=bv[/tex]
However at the fall, there is two more Force
[tex]F_2 = mg[/tex] (Gravity)
[tex]F_3 = ma[/tex](Net force)
So,
[tex]F_3 = F_2 - F_1[/tex]
[tex]ma = mg -bv[/tex]
[tex]a= g-\frac{bv}{m}[/tex]
For t/2
[tex]a(t/2) = g- \frac{b*\frac{x}{t/2}}{m}[/tex]
[tex]a(t/2) = g-2\frac{bx}{mt}[/tex]